[extractor/common] Generate better f4m format IDs

master
Philipp Hagemeister 10 years ago
parent 7adcbe7594
commit b252735910

@ -620,11 +620,15 @@ class InfoExtractor(object):
'Unable to download f4m manifest')
formats = []
for media_el in manifest.findall('{http://ns.adobe.com/f4m/1.0}media'):
media_nodes = manifest.findall('{http://ns.adobe.com/f4m/1.0}media')
for i, media_el in enumerate(media_nodes):
tbr = int_or_none(media_el.attrib.get('bitrate'))
format_id = 'f4m-%d' % (i if tbr is None else tbr)
formats.append({
'format_id': format_id,
'url': manifest_url,
'ext': 'flv',
'tbr': int_or_none(media_el.attrib.get('bitrate')),
'tbr': tbr,
'width': int_or_none(media_el.attrib.get('width')),
'height': int_or_none(media_el.attrib.get('height')),
})

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