[channel 9] Use centralized format sorting

master
Philipp Hagemeister 11 years ago
parent 12c978739a
commit a1b92edbb3

@ -76,14 +76,18 @@ class Channel9IE(InfoExtractor):
</div>)? # File size part may be missing
'''
# Extract known formats
formats = [{'url': x.group('url'),
'format_id': x.group('quality'),
'format_note': x.group('note'),
'format': '%s (%s)' % (x.group('quality'), x.group('note')),
'filesize': self._restore_bytes(x.group('filesize')), # File size is approximate
} for x in list(re.finditer(FORMAT_REGEX, html)) if x.group('quality') in self._known_formats]
# Sort according to known formats list
formats.sort(key=lambda fmt: self._known_formats.index(fmt['format_id']))
formats = [{
'url': x.group('url'),
'format_id': x.group('quality'),
'format_note': x.group('note'),
'format': u'%s (%s)' % (x.group('quality'), x.group('note')),
'filesize': self._restore_bytes(x.group('filesize')), # File size is approximate
'preference': self._known_formats.index(x.group('quality')),
'vcodec': 'none' if x.group('note') == 'Audio only' else None,
} for x in list(re.finditer(FORMAT_REGEX, html)) if x.group('quality') in self._known_formats]
self._sort_formats(formats)
return formats
def _extract_title(self, html):

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