[soundcloud] Remove limit on search results

master
reiv 9 years ago committed by Sergey M․
parent 417b453699
commit 328a22e175

@ -477,7 +477,7 @@ class SoundcloudPlaylistIE(SoundcloudIE):
class SoundcloudSearchIE(SearchInfoExtractor, SoundcloudIE):
IE_NAME = 'soundcloud:search'
IE_DESC = 'Soundcloud search'
_MAX_RESULTS = 200
_MAX_RESULTS = float('inf')
_TESTS = [{
'url': 'scsearch15:post-avant jazzcore',
'info_dict': {
@ -487,24 +487,28 @@ class SoundcloudSearchIE(SearchInfoExtractor, SoundcloudIE):
}]
_SEARCH_KEY = 'scsearch'
_RESULTS_PER_PAGE = 50
_MAX_RESULTS_PER_PAGE = 200
_DEFAULT_RESULTS_PER_PAGE = 50
_API_V2_BASE = 'https://api-v2.soundcloud.com'
def _get_collection(self, endpoint, collection_id, **query):
query['limit'] = self._RESULTS_PER_PAGE
query['limit'] = results_per_page = min(
query.get('limit', self._DEFAULT_RESULTS_PER_PAGE),
self._MAX_RESULTS_PER_PAGE)
query['client_id'] = self._CLIENT_ID
query['linked_partitioning'] = '1'
total_results = self._MAX_RESULTS
total_results = None
collected_results = 0
next_url = None
for i in itertools.count():
if not next_url:
query['offset'] = i * self._RESULTS_PER_PAGE
query['offset'] = i * results_per_page
data = compat_urllib_parse.urlencode(query)
next_url = '{0}{1}?{2}'.format(self._API_V2_BASE, endpoint, data)
next_url = '{0}{1}?{2}'.format(
self._API_V2_BASE, endpoint, data)
response = self._download_json(next_url,
video_id=collection_id,
@ -520,7 +524,8 @@ class SoundcloudSearchIE(SearchInfoExtractor, SoundcloudIE):
for item in filter(bool, collection):
yield item
if collected_results >= total_results or not collection:
if (total_results is not None and
collected_results >= total_results) or not collection:
break
next_url = response.get('next_href', None)
@ -528,7 +533,7 @@ class SoundcloudSearchIE(SearchInfoExtractor, SoundcloudIE):
def _get_n_results(self, query, n):
tracks = self._get_collection('/search/tracks',
collection_id='Query "{0}"'.format(query),
q=query.encode('utf-8'))
limit=n, q=query)
results = [self.url_result(url=track['uri'])
for track in itertools.islice(tracks, n)]

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